NCERT Exemplar Problems and Solutions (Part-IB) for CBSE Class 10 Mathematics chapter 6, Triangles, is available here. This part contains only the multiple choice type questions and a detailed solution is provided for each question. These questions will prove to be very helpful while preparing for CBSE Class 10 Board Exam 2017-2018.

Triangles NCERT Exemplar Problems, NCERT Exemplar Problems, Class 10 NCERT Exemplar Chapter 6

Find below the NCERT Exemplar problems and their solutions for Class 10 Mathematics Chapter, Triangles:

Exercise 6.1

Multiple Choice Questions (Q. No. 7-12)

Question. 7 In ΔABC and ΔDEF, B = ∠E, ∠F = ∠C and AB = 3DE then, the two triangles are

(a) congruent but not similar

(b) similar but not congruent

(c) neither congruent nor similar

(d) congruent as well as similar

Answer. (b)

Explanation:

Here, two triangles DABC and DDEF do not satisfy any rule of congruency, (SAS, ASA, SSS), so both are not congruent.

Answer. (a)

Explanation:

Question. 9 If ΔABC ~ ΔDFE, ∠A = 30°, ∠= 50°, AB = 5cm, AC = 8cm and DF = 7.5cm. Then, which of the following is true?

(a) DE =12cm, ∠F =50°    

(b) DE =12cm, ∠F =100°

(cEF =12cm, ∠D =100°  

(d) EF =12cm, ∠=30°

Answer. (b)

Explanation:

 

 

 

Answer. (c)

Explanation:

And, angle formed by DE and FD is ∠D.

So,          ∠B = ∠D

⟹           DABC ~ DEDF     (By SAS criterion)

Answer. (a)

Explanation:

As the ratio of area of two similar triangles is equal to the ratio of square of their corresponding sides.

Therefore, we get:

Question. 12 If S is a point on side PQ of a ΔPQR such that PS QS = RS, then

(a) PR . QR = RS2

(b) QS2 + RS2 =QR2

(c) PP2 + QPPQ2

(d) PS2 + RS2 = PR2

Answer. (c)          

Explanation:

 

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